Splitting Python String Into List Of Pairs

I have data in the following format: '22.926 g 47.377 g 73.510 g 131.567 g 322.744 g' What I would like to do is to split it into a list such that value and units are grouped toge

Solution 1:

With regex (and the re.findall method)you could obtain what you need :

import re
text="22.926 g 47.377 g 73.510 g 131.567 g 322.744 g"
re.findall("\d+\.\d+ g", text)
>>>['22.926 g', '47.377 g', '73.510 g', '131.567 g', '322.744 g']

But keep in mind that when solving a problem with regex we often end with 2 problems ;)

Solution 2:

a = "22.926 g 47.377 g 73.510 g 131.567 g 322.744 g".split()
c = [" ".join((v, g)) for v,g in zip(a[:-1:2], a[1::2])]

Solution 3:

what about splitting according to " g" and strip/filter out empty fields, re-add the g suffix afterwards, in one line:

["{} g".format(x.strip()) for x in"22.926 g 47.377 g 73.510 g 131.567 g 322.744 g".split(" g") if x]

result:

['22.926 g', '47.377 g', '73.510 g', '131.567 g', '322.744 g']

Solution 4:

In one-line! Split the string, and use list comprehension to get the desired output by removing all g and appending g!

s="22.926 g 47.377 g 73.510 g 131.567 g 322.744 g"
>>> [x+' g'forx in s.split() ifx!='g']

Output

['22.926 g', '47.377 g', '73.510 g', '131.567 g', '322.744 g']

Solution 5:

data = "22.926 g 47.377 g 73.510 g 131.567 g 322.744 g"sep = 'g'result = ['{digit} {sep}'.format(digit=d.strip(), sep=sep) for d in data[:-1].split(sep)]