Pass Command Line Parameters To Uwsgi Script

I'm trying to pass arguments to an example wsgi application, : config_file = sys.argv[1] def application(env, start_response): start_response('200 OK', [('Content-Type','text/

Solution 1:

python args:

--pyargv "foo bar"

sys.argv['uwsgi', 'foo', 'bar']

uwsgi options:

--set foo=bar

uwsgi.opt['foo']
'bar'

Solution 2:

You could use an .ini file with the pyargv setting that @roberto mentioned. Let's call our config file uwsgi.ini and use the content:

[uwsgi]wsgi-file=/path/to/test_uwsgi.py
pyargv=human

Then let's create a WGSI app to test it:

import sys
defapplication(env, start_response):
    start_response('200 OK', [('Content-Type','text/html')])
    return [str.encode("Hello " + str(sys.argv[1]), 'utf-8')]

You can see how to load this file https://uwsgi-docs.readthedocs.io/en/latest/Configuration.html#loading-configuration-files:

 uwsgi --ini /path/to/uwsgi.ini--http :8080

Then when we curl the app, we can see our param echoed back:

$ curl http://localhost:8080
Hello human

If you are trying to pass argparse style arguments to your WSGI app, they work just fine in the .ini too:

pyargv=-y /config.yml

Solution 3:

I ended up using an env variable but setting it inside a start script:

def start(uwsgi_conf, app_conf, logto):
    env = dict(os.environ)
    env[TG_CONFIG_ENV_NAME] = app_conf
    command = ('-c', uwsgi_conf, '--logto', logto, )
    os.execve(os.path.join(distutils.sysconfig.get_config_var('prefix'),'bin', 'uwsgi'), command, env)