Plot Datetime.timedelta Using Matplotlib And Python

I am working on a task, where I need to calculate time spent on each day and then represent that time using a bar plot, so for this task I used python and able to get time spent on

Solution 1:

I don't think you can directly plot timedelta in Matplotlib, but since you already have the number of seconds, you can define a custom tick format that converts seconds to hours and minutes.

from matplotlib.ticker import FuncFormatter

defformat_func(x, pos):
    hours = int(x//3600)
    minutes = int((x%3600)//60)
    seconds = int(x%60)

    return"{:d}:{:02d}".format(hours, minutes)
    # return "{:d}:{:02d}:{:02d}".format(hours, minutes, seconds)

formatter = FuncFormatter(format_func)

Then, you can set the tick formatter for the y-axis.

Here's an example using a bar.

labels = [2, 3, 4, 5, 8, 9, 10, 11, 12, 15, 16]
seconds = [i.seconds for i in time_list]
f = plt.figure()
ax = f.add_subplot(1,1,1)
ax.bar(labels, seconds)

ax.yaxis.set_major_formatter(formatter)
# this locates y-ticks at the hours
ax.yaxis.set_major_locator(matplotlib.ticker.MultipleLocator(base=3600))
# this ensures each bar has a 'date' label
ax.xaxis.set_major_locator(matplotlib.ticker.MultipleLocator(base=1))

Solution 2:

While matplotlib can in principle handle datetime objects, the bar plot cannot interprete them directly. So one may add an arbitrary date to the timedeltas and convert to numbers using matplotlib.dates.date2num(). Then using a DateFormatter enables nice ticklabels.

import numpy as np
import datetime
import matplotlib.pyplot as plt
import matplotlib.dates as mdates

days = [2, 3, 4, 5, 8, 9, 10, 11, 12, 15, 16]

time_list = [datetime.timedelta(0, 23820), datetime.timedelta(0, 27480), 
             datetime.timedelta(0, 28500), datetime.timedelta(0, 24180), 
             datetime.timedelta(0, 27540), datetime.timedelta(0, 28920), 
             datetime.timedelta(0, 28800), datetime.timedelta(0, 29100), 
             datetime.timedelta(0, 29100), datetime.timedelta(0, 24480), 
             datetime.timedelta(0, 27000)]

# specify a date to use for the times
zero = datetime.datetime(2018,1,1)
time = [zero + t for t in time_list]
# convert datetimes to numbers
zero = mdates.date2num(zero)
time = [t-zero for t in mdates.date2num(time)]

f = plt.figure()
ax = f.add_subplot(1,1,1)

ax.bar(days, time, bottom=zero)
ax.yaxis_date()
ax.yaxis.set_major_formatter(mdates.DateFormatter("%H:%M"))# add 10% margin on top (since ax.margins seems to not work here)
ylim = ax.get_ylim()
ax.set_ylim(None, ylim[1]+0.1*np.diff(ylim))

plt.show()

Solution 3:

I had similar problem when I wanted to plot the data with a y axis equal to Timedelta64[ns] type. I found the easiest solution to handle this issue from this blog : solution. For short, just change the dtype of your column to .astype('timedelta64[m]'). You can change to hour, minutes or seconds for your case just by changing the value in a square brackets. It changes the dtype of your y column to float64 and then you can easily plot the bar graph or plot with normal units and not like nanoseconds